1.这个飞狐的飞狐副图飞狐极速文库源码副如何修改才能用来作为通达信的副呢?
这个飞狐的副如何修改才能用来作为通达信的副呢?
rsv:=(c-llv(l,7))/(hhv(h,7)-llv(l,7))*;
rsv1:=(c-llv(l,))/(hhv(h,)-llv(l,))*;
流金:sma(rsv1,5,1),colorfff;
岁月:sma(流金,,1),colorcc;
drawband(流金,rgb(,0,0),岁月,rgb(0,,0));
var2q:=ma(c,)-ma(c,)/3;
神奇线:=ma((c-var2q)/var2q,1);
xa:=ema(神奇线,)*0.7;
xb:=ema(神奇线,3);
底部区域:if(llv(xb-xa,)>0,0,-),Linethick2,colorff;
diff:=(ema(c,)-ema(c,))*;
dea:=ema(diff,);
macd:=2*(diff-dea);
stickline(diff<=0 and dea<=diff and ref(diff,1)<ref(dea,1),3,,3,0),Linethick2,colorffff;
if(diff<=0 and dea<=diff and ref(diff,1)<ref(dea,1),,0),colorff;
var1:=(c-ref(c,1))/ref(c,1)*;
var2:=(indexc-ref(indexc,1))/ref(indexc,1)*;
var3:=ema(sum(var1,),3);
var4:=ema(sum(var2,),3);
var5:=(var3-var4);
drawicon(var5<- and filter(var5>ref(var5,2),7),0,1);
drawicon(var5> and filter(var5<ref(var5,2),7),,2);
a1:=ma(c,);
zx:=ref(a1,/2+1);
b1:=cross(c,zx);
s1:=cross(zx,c);
drawicon(cross(c,zx),-3,);
drawicon(c>zx and ref(c,1)>ref(zx,1),-3,);
drawicon(c<zx and ref(c,1)>ref(zx,1),-3,);
lgl:=c-ref(ma(c,),);
wr1:=if(ema(c,5)/ema(ema(c,9),)<=0. and c/ref(c,1)>0. and c/ref(c,1)<1. and v/capital*<5,,0);
wr2:=-(*(hhv(h,)-c)/(hhv(h,)-llv(l,)))+*lgl;
wr3:=-(*(hhv(h,)-c)/(hhv(h,)-llv(l,)))+;
bias1:=-(*(hhv(h,)-c)/(hhv(h,)-llv(l,)))+*lgl;
bias2:=((c-ma(c,))/ma(c,)*+)*5;
bias3:=((c-ma(c,))/ma(c,)*+)*5;
sx:=((c-ma(c,))/ma(c,)*+)*5;
s:=(wr2+wr3+bias1+bias2+bias3+sx)/6*lgl;
ccc:=abs(bias2-sx);
zjz:=(s+ccc)/2;
lxl:=(-1)*(ema(*(1-winner(c)),1)-)+;
jbj:=lxl+zjz;
ma3:=if(wr1>0 and jbj<0,,0)*lgl;
c0:=if(zjz<0 and c=llv(c,5) and c/ref(c,1)>0. and c/ref(c,1)<1. and v/capital*<5,-,0);
bot:=if(jbj<0 and c0=-,,0)*lgl;
cxc:=ref(c,2)*0.;
vmc:=ref(c,)*0.;
v:=min(cxc,vmc);
v:=*v/capital*lgl;
半年线:=(c-v)/c<3/ and sum(v,5)/5<1.8;
预测:=半年线>0 and (c0<0 or wr1>0);
if(ma3>0 and bot>0 and sum(v/capital*,5)/5<1 or 半年线>0 and ref(c,1)/ref(c,2)>0. or
(ma3>0 and bot>0 and sum(v/capital*,5)/5<1 or 半年线>0) and (c0<0 or wr1>0) and 预测<,,0),Linethick2,colorffff;
a:=ema(winner(c),);
b:=ema(winner(c),);
var:=ma(v,5)>ma(v,);
追涨:if(a<0. and abs(a-b)<0. and cross(a,b) and var,,0),Linethick2,colorffcc;
if(a>0.9 and c<ma(c,5),,),Linethick2,colorred;
sma(var,3,1),colorfff0;
股神:3*sma((c-llv(l,))/(hhv(h,)-llv(l,))*,5,1)-2*sma(sma((c-llv(l,))/(hhv(h,)-llv(l,))*,5,1),3,1),colorff;
短线进出:if(股神<=,-,0);
if(cross(股神,)AND 岁月<,,0),Linethick2;
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