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时间:2024-12-29 03:44:36 来源:同城分类app源码 分类:热点

1.如何解决android 5.0中出现的警告service intent must be expl

getApplicationInfo源码

如何解决android 5.0中出现的警告service intent must be expl

       æœ‰äº›æ—¶å€™æˆ‘们使用Service的时需要采用隐私启动的方式,但是Android 5.0一出来后,其中有个特性就是Service Intent must be explitict,也就是说从Lollipop开始,service服务必须采用显示方式启动。

       è€Œandroid源码是这样写的(源码位置:sdk/sources/android-/android/app/ContextImpl.java):

       private void validateServiceIntent(Intent service) {

        if (service.getComponent() == null && service.getPackage() == null) {

        if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {

        IllegalArgumentException ex = new IllegalArgumentException(

        "Service Intent must be explicit: " + service);

        throw ex;

        } else {

        Log.w(TAG,源码怎么去读源码 "Implicit intents with startService are not safe: " + service

        + " " + Debug.getCallers(2, 3));

        }

        }

        }

       å¤åˆ¶ä»£ç 

       æ—¢ç„¶ï¼Œæºç é‡Œæ˜¯è¿™æ ·å†™çš„,那么这里有两种解决方法:

       1、设置Action和packageName:

       å‚考代码如下:

       Intent mIntent = new Intent();

       mIntent.setAction("XXX.XXX.XXX");//你定义的service的action

       mIntent.setPackage(getPackageName());//这里你需要设置你应用的包名

       context.startService(mIntent);

       å¤åˆ¶ä»£ç 

       æ­¤æ–¹å¼æ˜¯google官方推荐使用的解决方法。

       2、将隐式启动转换为显示启动:

       public static Intent getExplicitIntent(Context context, Intent implicitIntent) {

        // Retrieve all services that can match the given intent

        PackageManager pm = context.getPackageManager();

        List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);

        // Make sure only one match was found

        if (resolveInfo == null || resolveInfo.size() != 1) {

        return null;

        }

        // Get component info and create ComponentName

        ResolveInfo serviceInfo = resolveInfo.get(0);

        String packageName = serviceInfo.serviceInfo.packageName;

        String className = serviceInfo.serviceInfo.name;

        ComponentName component = new ComponentName(packageName, className);

        // Create a new intent. Use the old one for extras and such reuse

        Intent explicitIntent = new Intent(implicitIntent);

        // Set the component to be explicit

        explicitIntent.setComponent(component);

        return explicitIntent;

        }

       å¤åˆ¶ä»£ç 

       è°ƒç”¨æ–¹å¼å¦‚下:

       Intent mIntent = new Intent();

       mIntent.setAction("XXX.XXX.XXX");

       Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));

       context.startService(eintent);